92=7e^2

Solution for 92=7e^2 equation:

92=7e^2

We move all terms to the left:

92-(7e^2)=0

a = -7; b = 0; c = +92;
Δ = b2-4ac
Δ = 02-4·(-7)·92
Δ = 2576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2576}=\sqrt{16*161}=\sqrt{16}*\sqrt{161}=4\sqrt{161}$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{161}}{2*-7}=\frac{0-4\sqrt{161}}{-14}
=-\frac{4\sqrt{161}}{-14}
=-\frac{2\sqrt{161}}{-7}
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{161}}{2*-7}=\frac{0+4\sqrt{161}}{-14}
=\frac{4\sqrt{161}}{-14}
=\frac{2\sqrt{161}}{-7}
$